Understanding the Solubility of Compounds in Water

What is the correct order of solubility of the following compounds in water?

a) n-butanol Isopropyl alcohol > 2-methyl-2-propanol > Isobutanol

b) 2-methyl-2-propanol Isopropyl alcohol isobutanol > n-butanol

c) Isopropyl alcohol 2-methyl-2-propanol > Isobutanol > n-butanol

d) 2-methyl-2-propanol Isobutanol isopropyl alcohol n-butanol

Answer:

The correct order of solubility in water is: isopropyl alcohol > 2-methyl-2-propanol > Isobutanol > n-butanol. Therefore, the correct option is c.

The correct arrangement of the compounds in the order of solubility in water is: c) isopropyl alcohol > 2-methyl-2-propanol > Isobutanol > n-butanol. This order is based on the polarity of the compounds.

Isopropyl alcohol is the most soluble compound in water due to its ability to form hydrogen bonds. It is followed by 2-methyl-2-propanol, Isobutanol, and finally n-butanol, with n-butanol being the least soluble.

Understanding the solubility of compounds in water is important in various fields of science and can have practical applications in industries such as pharmaceuticals and chemical engineering.

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