# Basketball Gauge Pressure Calculation

## What is the gauge pressure of a basketball when you push it down with a force of 30 N?

A basketball is being pushed down with a force of 30 N, causing the ball to flatten out. If the bottom of the ball forms a circular area with a diameter of 2.5 cm, what is the gauge pressure inside the basketball?

## Answer:

The gauge pressure of the basketball when pushed down with a force of 30 N is 32.5 N.

To calculate the gauge pressure of the basketball in this scenario, we can use the formula for pressure:

**Pressure = Force / Area**

Given that the force applied is 30 N and the bottom of the basketball forms a circular area with a diameter of 2.5 cm, we first need to calculate the radius of the circle:

**Radius = Diameter / 2 = 2.5 cm / 2 = 1.25 cm = 0.0125 m**

Next, we calculate the area of the circular bottom of the basketball:

**Area = π * (radius)^2 = π * (0.0125 m)^2 ≈ 0.000491 m^2**

Now, plug the values into the pressure formula:

**Pressure = 30 N / 0.000491 m^2 ≈ 32.5 N**

Therefore, when a force of 30 N is applied to the basketball, the gauge pressure inside the basketball is approximately 32.5 N.