# Find the Braking Force Calculation for a 4500 kg Truck

## What is the task in this problem?

Calculate the braking force needed to bring a 4500 kg truck to a stop from a speed of 20 m/s in 9 s.

## What are the given values?

Mass of the truck (m) = 4500 kg

Initial speed of the truck (u) = 20 m/s

Time required (t) = 9 s

## What needs to be determined?

The braking force required to stop the truck

## Answer:

The braking force needed to bring the 4500 kg truck to a stop is 9990 N.

In this problem, we are asked to calculate the braking force required to bring a 4500 kg truck to a stop from an initial speed of 20 m/s in 9 seconds.

Given:

- Mass of the truck, m = 4500 kg
- Initial speed of the truck, u = 20 m/s
- Time required, t = 9 s

To find the braking force, we first calculate the acceleration of the truck using the formula:

Acceleration (a) = (final velocity - initial velocity) / time

Since the truck comes to a stop, the final velocity is 0. Therefore, the acceleration is calculated as:

Acceleration (a) = (0 m/s - 20 m/s) / 9 s = -2.22 m/s^2

The negative sign indicates deceleration, meaning the truck is slowing down. We then use the formula F = ma to find the braking force:

Braking Force (F) = 4500 kg * 2.22 m/s^2 = 9990 N

Therefore, the braking force required to bring the 4500 kg truck to a stop from a speed of 20 m/s in 9 s is 9990 N.