# What Happens When a 200 W Light Bulb is Connected to a 110 V DC Power Supply?

## What current will flow through the bulb?

## What is the resistance of the light bulb?

(A) The current will flow through this bulb will be 1.8 amps

(B) The resistance of the light bulb will be 60.5 ohms

## Explanation:

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The given data in the problem is:

P is the power = 200 W

V is the voltage = 110 V

I is the current

R is the resistance

### Calculating the Current:

The relationship between power and voltage is given by:

P = IV

I = P/V

I = 200/110

I = 1.8 amps

Therefore, the current flowing through the bulb will be 1.8 amps.

### Calculating the Resistance:

The relationship between power and resistance is given by:

P = V^2/R

R = V^2/P

R = 110^2/200

R = 60.5 ohms

Therefore, the resistance of the light bulb will be 60.5 ohms.